0=(7k^2)-8

Solution for 0=(7k^2)-8 equation:

0=(7k^2)-8

We move all terms to the left:

0-((7k^2)-8)=0

We add all the numbers together, and all the variables

-(7k^2-8)=0

We get rid of parentheses

-7k^2+8=0

a = -7; b = 0; c = +8;
Δ = b2-4ac
Δ = 02-4·(-7)·8
Δ = 224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{224}=\sqrt{16*14}=\sqrt{16}*\sqrt{14}=4\sqrt{14}$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{14}}{2*-7}=\frac{0-4\sqrt{14}}{-14}
=-\frac{4\sqrt{14}}{-14}
=-\frac{2\sqrt{14}}{-7}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{14}}{2*-7}=\frac{0+4\sqrt{14}}{-14}
=\frac{4\sqrt{14}}{-14}
=\frac{2\sqrt{14}}{-7}
$